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Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is-
Answer & Solution
Correct Answer:
Option
D
Let the fourth number be x
Then, third number = 5x
Second number = $$\frac{5x}{3}$$ and
First number = $$\frac{10x}{3}$$
x + 5x + $$\frac{5x}{3}$$ + $$\frac{10x}{3}$$ = (24.75 × 4)
⇒ 11x = 99
⇒ x = 9
So, the numbers are 9, 45, 15 and 30
∴ Largest number = 45
Then, third number = 5x
Second number = $$\frac{5x}{3}$$ and
First number = $$\frac{10x}{3}$$
x + 5x + $$\frac{5x}{3}$$ + $$\frac{10x}{3}$$ = (24.75 × 4)
⇒ 11x = 99
⇒ x = 9
So, the numbers are 9, 45, 15 and 30
∴ Largest number = 45
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