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One black, one red and one green dice are thrown together, what is the probability of sum of three numbers is ≥ 17.
Answer & Solution
Correct Answer:
Option
C
Total events = 63 = 216
Sum greater than 17 = (6, 6, 6)
Sum equal to 17 = (6, 6, 5)(6, 5, 6)(5, 6, 6)
Probability = $$\frac{4}{{216}}$$ = $$\frac{1}{{54}}$$
Sum greater than 17 = (6, 6, 6)
Sum equal to 17 = (6, 6, 5)(6, 5, 6)(5, 6, 6)
Probability = $$\frac{4}{{216}}$$ = $$\frac{1}{{54}}$$
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