ExamVeda
Login
Home

Reenu's father was 38 years of age when she was born...

This question belongs to Arithmetic Ability Problems On Ages
Problems on Ages
?

Reenu's father was 38 years of age when she was born while her mother was 36 years old when her brother 4 years younger to her was born. What is the difference between the ages of her parents ?

Answer & Solution
Correct Answer: Option C
Mother's age when Reenu's brother was born = 36 year
Father's age when Reenu's brother was born = (38 + 4) years = 42 year
Required difference = (42 - 36) years = 6 years
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.
Keep Learning

Related Questions on Problems on Ages

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A. 2 times B. $$2\frac{1}{2}\,{\text{times}}$$ C. $$2\frac{3}{4}\,{\text{times}}$$ D. 3 times
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A. 4 years B. 8 years C. 10 years D. None of these
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
A. 14 years B. 19 years C. 33 years D. 38 years
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A. 7 B. 8 C. 9 D. 10 E. 11
More Related Questions on Problems on Ages