$$\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}$$     is equal to = ?

A. $$\sqrt 6 $$

B. $$\frac{{\sqrt 3 }}{2}$$

C. $$\frac{{\sqrt 2 }}{3}$$

D. $$\frac{{\sqrt 6 }}{2}$$

Answer: Option D

Solution(By Examveda Team)

$$\eqalign{ & {\text{According to the question,}} \cr & \frac{{\sqrt {72} - \sqrt {18} }}{{\sqrt {12} }} \cr & \Rightarrow \sqrt {\frac{{72}}{{12}}} - \sqrt {\frac{{18}}{{12}}} \cr & \Rightarrow \sqrt 6 - \sqrt {\frac{6}{4}} \cr & \Rightarrow \frac{{\sqrt 6 }}{2} \cr} $$