?
The value of $$\frac{{{{\left( {a + b} \right)}^2}}}{{\left( {{a^2} - {b^2}} \right)}}{\text{is}}\, = {\text{?}}$$
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \frac{{{{\left( {a + b} \right)}^2}}}{{\left( {{a^2} - {b^2}} \right)}} \cr
& = \frac{{\left( {a + b} \right)\left( {a + b} \right)}}{{\left( {a + b} \right)\left( {a - b} \right)}} \cr
& = \frac{{a + b}}{{a - b}}\, \cr} $$
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