The value of $$\frac{{{{\left( {a + b} \right)}^2}}}{{\left( {{a^2} - {b^2}} \right)}}{\text{is}}\, = {\text{?}}$$

A. $$\frac{{ab}}{{a + b}}$$

B. $$\frac{{2ab}}{{a - b}}$$

C. $$\frac{{a + b}}{{a - b}}$$

D. None of these

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & \frac{{{{\left( {a + b} \right)}^2}}}{{\left( {{a^2} - {b^2}} \right)}} \cr & = \frac{{\left( {a + b} \right)\left( {a + b} \right)}}{{\left( {a + b} \right)\left( {a - b} \right)}} \cr & = \frac{{a + b}}{{a - b}}\, \cr} $$