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This question belongs to Arithmetic Ability Trigonometry

Trigonometry

?

Solve the following to find its value in terms of trigonometric ratios.
(sinA + cosA)(1 - sinAcosA)

A) sin³A + cos³A B) sin²A - cos²A C) [cosA - sinA][sin²A + cos²A] D) sin³A - cos³A

Answer & Solution

Correct Answer: Option A

(sinA + cosA)(1 - sinA.cosA)
= (sinA + cosA)[sin²A + cos²A - sinA.cosA]
= (sin³A + cos³A)

Question posted by Examveda

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