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The average of a collection of 20 measurements was calculated to tb 56 cm. But later it was found that a mistake had occurred in one of the measurement which was recorded as 64 cm., but should have been 61 cm. The correct average must be -
Answer & Solution
Correct Answer:
Option
C
According to the question,
Correct average
= $$\frac{20 × 56 - 64 + 61}{20}$$
= $$\frac{1120 - 3}{20}$$
= $$\frac{1117}{20}$$
= 55.85 cm
Correct average
= $$\frac{20 × 56 - 64 + 61}{20}$$
= $$\frac{1120 - 3}{20}$$
= $$\frac{1117}{20}$$
= 55.85 cm
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