The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then-
A. x = y + z
B. 2x = y + z
C. x = 2y + 2z
D. None of these
Answer: Option B
Solution (By Examveda Team)
Clearly, we have :$$\eqalign{ & \Rightarrow x = \left( {\frac{{3y + 3z}}{6}} \right) \cr & \Rightarrow 2x = y + z \cr} $$
This Question Belongs to Arithmetic Ability >> Average
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