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The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then-
Answer & Solution
Correct Answer:
Option
B
Clearly, we have :
$$\eqalign{ & \Rightarrow x = \left( {\frac{{3y + 3z}}{6}} \right) \cr & \Rightarrow 2x = y + z \cr} $$
$$\eqalign{ & \Rightarrow x = \left( {\frac{{3y + 3z}}{6}} \right) \cr & \Rightarrow 2x = y + z \cr} $$
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