The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then-

A. x = y + z

B. 2x = y + z

C. x = 2y + 2z

D. None of these

Answer: Option B

Solution(By Examveda Team)

Clearly, we have :
$$\eqalign{ & \Rightarrow x = \left( {\frac{{3y + 3z}}{6}} \right) \cr & \Rightarrow 2x = y + z \cr} $$