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The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is -
Answer & Solution
Correct Answer:
Option
D
Max - Min = 172.....(i)
Max + Min = 50 × 40 - 48 × 38
Max + Min = 2000 - 1824
Max + Min = 176.....(ii)
From equation (i) and (ii)
Max = 174
Max + Min = 50 × 40 - 48 × 38
Max + Min = 2000 - 1824
Max + Min = 176.....(ii)
From equation (i) and (ii)
Max = 174
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