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This question belongs to Electronics And Communications Engineering Digital Electronics

Digital Electronics

?

The binary code of (21.125)10 is

A) 10101.001 B) 10100.001 C) 10101.010 D) 10100.111

Answer & Solution

Correct Answer: Option A

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Question posted by Examveda

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Rehmat Ali 3 years ago

21 ÷ 2 = 10 remainder 1
10 ÷ 2 = 5 remainder 0
5 ÷ 2 = 2 remainder 1
2 ÷ 2 = 1 remainder 0
1 ÷ 2 = 0 remainder 1
0.125 × 2 = 0.25 → Integer part: 0
0.25 × 2 = 0.5 → Integer part: 0
0.5 × 2 = 1.0 → Integer part: 1

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