The chromium (III) species formed soon after electron transfer between $$IrCl_6^{2 - }$$ and $$Cr\left( {{H_2}O} \right)_6^{2 + }$$ is
A. $$Cr\left( {{H_2}O} \right)_6^{3 + }$$
B. $$Cr{\left( {{H_2}O} \right)_5}C{l^{2 + }}$$
C. $$CrCl_6^{2 - }$$
D. $$Cr{\left( {{H_2}O} \right)_3}C{l_3}$$
Answer: Option A
This Question Belongs to Engineering Chemistry >> Transition Elements
Related Questions on Transition Elements
A. Lu3+, Yb3+, Dy3+, Eu3+
B. Eu3+, Dy3+, Yb3+, Lu3+
C. Dy3+, Yb3+, Eu3+, Lu3+
D. Yb3+, Dy3+, Lu3+ , Eu3+
A. D4h and (C2v and C2h)
B. Td and (C2v and D4h)
C. D4h and (C2v and D4h)
D. Td and (C2v and C4v)
The complex that exists as a pair of enantiomers is
A. trans-[CO(H2NCH2CH2NH2)2Cl2]+
B. cis-[Co(NH3)4Cl2]+
C. [Pt(PPh3)(Cl)(Br)(CH3)]-
D. [Co(H2NCH2CH2NH2)3]3+
The complex formed in the brown ring test for nitrates is
A. [Fe(H2O)5NO]3+
B. [Fe(H2O)5NO]2+
C. [Fe(H2O)4(NO)]2+
D. [Fe(H2O)4(NO)]3+
Join The Discussion