The depth of center of pressure of an immersed surface, inclined at an angle with the liquid surface lies at a distance equal to __________ the center of gravity.

This question belongs to Mechanical Engineering Hydraulics And Fluid Mechanics In ME

Hydraulics and Fluid Mechanics in ME

The depth of center of pressure of an immersed surface, inclined at an angle $$\theta $$ with the liquid surface lies at a distance equal to __________ the center of gravity.

A) $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$ B) $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$ C) $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$ D) $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$

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Correct Answer: Option A

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Krishan Gehlot 8 years ago

Please explain

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The depth of center of pressure of an immersed surface inclined...

The depth of center of pressure of an immersed surface, inclined at an angle $$\theta $$ with the liquid surface lies at a distance equal to __________ the center of gravity.

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