The depth of center of pressure of an immersed surface, inclined at an angle $$\theta $$ with the liquid surface lies at a distance equal to __________ the center of gravity.
A. $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$
B. $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$
C. $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$
D. $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$
Answer: Option A
This Question Belongs to Mechanical Engineering >> Hydraulics And Fluid Mechanics In ME
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