The depth of center of pressure of an immersed surface, inclined at an angle $$\theta $$ with the liquid surface lies at a distance equal to __________ the center of gravity.

A. $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$

B. $$\frac{{{I_{\text{G}}}{{\sin }^2}\theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$

C. $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ below}}$$

D. $$\frac{{{I_{\text{G}}}\sin \theta }}{{{\text{A}}\overline {\text{x}} }}{\text{ above}}$$

Answer: Option A