The . . . . . . . . inhibition gives the following rate equation.
$$V = {{{V_{\max }}\left[ S \right]} \over {{K_m} + \left[ S \right]\left( {1 + {{\left[ S \right]} \over {{K_s}}}} \right)}}$$
A. Substrate
B. Mixed
C. Non-competitive
D. Competitive
Answer: Option A
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