The lowest temperature during the cycle in a vapour compression system...

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The lowest temperature during the cycle in a vapour compression system occurs after

A. Compression

B. Expansion

C. Condensation

D. Evaporation

Answer: Option D

Solution(By Examveda Team)

The lowest temperature during the cycle in a vapour compression system occurs after Evaporation

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  1. SAM Mourya
    SAM Mourya :
    4 years ago

    ๐‘จ๐’‡๐’•๐’†๐’“ ๐’†๐’™๐’‘๐’‚๐’๐’”๐’Š๐’๐’ ๐’๐’๐’˜๐’†๐’”๐’• ๐’•๐’†๐’Ž๐’‘๐’†๐’“๐’‚๐’•๐’–๐’“๐’† ๐’‘๐’๐’”๐’”๐’Š๐’ƒ๐’๐’† ๐’‰๐’‚๐’Š.
    ๐‘จ๐’ˆ๐’‚๐’“ ๐’ƒ๐’‚๐’‚๐’• ๐’‘๐’“๐’‚๐’„๐’•๐’Š๐’„๐’‚๐’๐’๐’š ๐’‰๐’ ๐’•๐’ƒ..... ๐‘บ๐’–๐’“๐’† ๐’‰๐’–๐’Ž ๐’‚๐’‡๐’•๐’†๐’“ ๐’†๐’™๐’‘๐’†๐’๐’”๐’Š๐’๐’ ๐’๐’๐’˜๐’†๐’”๐’• ๐’•๐’†๐’Ž๐’‘๐’†๐’“๐’‚๐’•๐’–๐’“๐’† ๐’๐’ˆ๐’‚ ๐’”๐’Œ๐’•๐’† ๐’‰๐’‚๐’Š, ๐’ƒ๐’„๐’› ๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’๐’“ ๐’•๐’Œ ๐’‚๐’‚๐’๐’† ๐’Ž๐’† ๐’Œ๐’–๐’„๐’‰ ๐’‡๐’๐’–๐’Š๐’… ๐’‡๐’“๐’Š๐’„๐’•๐’Š๐’๐’ ๐’‰๐’๐’ˆ๐’‚ ๐’Š๐’”๐’๐’Š๐’š๐’† ๐’‚๐’” ๐’„๐’๐’Ž๐’‘๐’‚๐’Š๐’“ ๐’•๐’ ๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’๐’“ ๐’†๐’™๐’‘๐’‚๐’๐’”๐’Š๐’๐’ ๐’Ž๐’† ๐’๐’๐’˜๐’†๐’”๐’• ๐’•๐’†๐’Ž๐’‘๐’†๐’“๐’‚๐’•๐’–๐’“๐’† ๐’Ž๐’Š๐’๐’†๐’ˆ๐’‚....เคฒเฅ‡เค•เคฟเคจ เคฒเฅ‡เค•เคฟเคจ เคฒเฅ‡เค•เคฟเคจ....๐’‚๐’ˆ๐’‚๐’“ ๐’ƒ๐’‚๐’‚๐’• ๐’•๐’‰๐’†๐’๐’“๐’†๐’•๐’Š๐’„๐’‚๐’๐’๐’š ๐’‰๐’ ๐’•๐’???
    1. ๐‘ป๐’†๐’Ž๐’‘๐’“๐’‚๐’•๐’–๐’“๐’† ๐’•๐’ ๐’๐’๐’˜๐’†๐’”๐’• ๐’†๐’™๐’‘๐’†๐’๐’”๐’Š๐’๐’ ๐’Œ๐’† ๐’ƒ๐’‚๐’‚๐’… ๐’‰๐’Š ๐’‰๐’๐’ˆ๐’‚...(๐’ƒ๐’–๐’• ๐’‚๐’„๐’„๐’๐’“๐’…๐’Š๐’๐’ˆ ๐’•๐’ ๐’‚๐’๐’”๐’˜๐’†๐’“ ๐’‹๐’ ๐’Œ๐’Š ๐‘ซ๐‘ซ๐‘ซ ๐’…๐’† ๐’“๐’‰๐’‚ ๐’‰๐’‚๐’Š ๐’Œ๐’–๐’„๐’‰ ๐’”๐’•๐’–๐’…๐’†๐’๐’•๐’” ๐’Œ๐’‚ ๐’Œ๐’‚๐’‰๐’๐’‚ ๐’‰๐’‚๐’Š....)
    2. ๐‘จ๐’ˆ๐’‚๐’“ #๐’…๐’–๐’“๐’Š๐’๐’ˆ_๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’๐’“(๐’๐’๐’• ๐’‚๐’‡๐’•๐’†๐’“) ๐’‰๐’๐’•๐’‚ ๐’•๐’ƒ ๐’Œ๐’–๐’„๐’‰ ๐’ƒ๐’‚๐’‚๐’• ๐’ƒ๐’ ๐’”๐’Œ๐’•๐’‚ ๐’•๐’‰๐’‚ ๐’ƒ๐’„๐’›, ๐’Š๐’ ๐’•๐’‰๐’Š๐’” ๐’‘๐’“๐’๐’„๐’†๐’”๐’” ๐’•๐’†๐’Ž๐’‘๐’“๐’‚๐’•๐’–๐’“๐’† ๐’„๐’‚๐’'๐’• ๐’Š๐’๐’„๐’“๐’†๐’‚๐’”๐’†๐’” ๐’๐’๐’๐’š ๐’๐’‚๐’•๐’†๐’๐’• ๐’‰๐’†๐’‚๐’• ๐’Š๐’” ๐’‚๐’ƒ๐’”๐’๐’“๐’ƒ๐’†๐’…....
    ๐‘ป๐’‰๐’Š๐’” ๐’Š๐’” ๐’‚/๐’„ ๐’•๐’ ๐’Ž๐’†....(๐‘ฐ ๐’•๐’‰๐’Š๐’๐’Œ)
    เค‡เคธเค•เคพ เคเค• ๐’†๐’™๐’‚๐’Ž๐’‘๐’๐’† เคธเฅ‡ ๐’Š ๐’•๐’‰๐’Š๐’๐’Œ เคธเคฎเคเคพ เคœเคพ เคธเค•เคคเคพ เคนเฅˆ:-
    เคœเคฌ เคนเคฎ เค…เคชเคจเฅ€ ๐’—๐’†๐’‰๐’Š๐’„๐’๐’†๐’” เคฎเฅ‡เค‚ เคนเคตเคพ เคญเคฐเคตเคพเคจเฅ‡ เคœเคพเคคเฅ‡ เคนเฅˆ เคคเฅ‹ เค•เฅ‹ ๐’‚๐’Š๐’“-๐’”๐’•๐’๐’“๐’‚๐’ˆ๐’†๐’†( ๐’‚๐’Š๐’“-๐’„๐’๐’Ž๐’‘๐’“๐’†๐’”๐’”๐’๐’“) เคœเคนเคพ เคธเฅ‡ เคนเคตเคพ เคจเคฟเค•เคฒเคคเคพ เคนเฅˆ เคตเคนเคพ เคชเฅ‡ เค เค‚เคกเคพ ๐’‡๐’†๐’†๐’ เคนเฅ‹เคคเคพ เคนเฅˆ.....เค…เคฌ เค‰เคธเฅ€ เค•เฅ‹ เค•เคฟเคธเฅ€ เคชเคพเค‡เคช เค•เฅ‡ ๐’•๐’‰๐’“๐’๐’–๐’ˆ๐’‰ เคฒเฅ‡ เคœเคพเคเค‚เค—เฅ‡ เคคเฅ‹ ๐’‡๐’๐’–๐’Š๐’… ๐’‡๐’“๐’Š๐’„๐’•๐’Š๐’๐’ เค•เฅ‡ เค•เคพเคฐเคฃ ๐’•๐’†๐’Ž๐’‘๐’“๐’‚๐’•๐’–๐’“๐’† เคคเฅ‹ ๐’“๐’Š๐’”๐’† เค•เคฐเฅ‡เค—เคพ เคนเฅ€เฅค ๐‘ฐ๐’”๐’๐’Š๐’š๐’† ๐’‚๐’‡๐’•๐’†๐’“ ๐’†๐’™๐’๐’†๐’๐’”๐’Š๐’๐’ ๐’๐’๐’˜๐’†๐’”๐’• ๐’‘๐’๐’”๐’”๐’Š๐’ƒ๐’๐’† ๐’•๐’†๐’Ž๐’‘๐’“๐’‚๐’•๐’–๐’“๐’† ๐’Š๐’” ๐’‘๐’๐’”๐’”๐’Š๐’ƒ๐’๐’† ๐Ÿ‘๐Ÿ‘

    ๐‘บ๐’Š๐’๐’„๐’†, ๐’Š๐’• ๐’•๐’‚๐’Œ๐’†๐’” ๐’‰๐’†๐’‚๐’• ๐’…๐’–๐’“๐’Š๐’๐’ˆ ๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’Š๐’๐’ ๐’‚๐’๐’… ๐’ˆ๐’†๐’•๐’” ๐’”๐’–๐’‘๐’†๐’“๐’‰๐’†๐’‚๐’•๐’†๐’… ๐’˜๐’Š๐’•๐’‰๐’Š๐’ ๐’‚ ๐’„๐’†๐’“๐’•๐’‚๐’Š๐’ ๐’…๐’†๐’ˆ๐’“๐’†๐’† ๐’๐’‡ ๐’”๐’–๐’‘๐’†๐’“๐’‰๐’†๐’‚๐’•(๐’…๐’–๐’“๐’Š๐’๐’ˆ ๐’…๐’“๐’š ๐’„๐’๐’Ž๐’‘๐’“๐’†๐’”๐’”๐’Š๐’๐’)... ๐‘บ๐’ ๐’•๐’†๐’Ž๐’‘๐’†๐’“๐’‚๐’•๐’–๐’“๐’† ๐’˜๐’Š๐’๐’ ๐’ƒ๐’† ๐’‰๐’Š๐’ˆ๐’‰๐’†๐’“ ๐’‚๐’‡๐’•๐’†๐’“ ๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’Š๐’๐’ ๐’•๐’‰๐’‚๐’ ๐’‚๐’‡๐’•๐’†๐’“ ๐’†๐’™๐’‘๐’‚๐’๐’”๐’Š๐’๐’...

    ๐‘บ๐’, ๐’‚๐’‡๐’•๐’†๐’“ ๐’†๐’™๐’‘๐’†๐’๐’”๐’Š๐’๐’ ๐’‚๐’๐’… ๐’ƒ๐’†๐’‡๐’๐’“๐’† ๐’†๐’—๐’‚๐’‘๐’๐’“๐’‚๐’•๐’๐’“ ๐’๐’๐’˜๐’†๐’”๐’• ๐’•๐’†๐’Ž๐’‘๐’†๐’“๐’‚๐’•๐’–๐’“๐’† ๐’˜๐’Š๐’๐’ ๐’ƒ๐

  2. Saurabh Kumar
    Saurabh Kumar :
    4 years ago

    Correct answer is (B).. as it takes heat during evaporation and gets superheated within a certain degree of superheat... So temperature will be higher after evaporation than after expansion...

Related Questions on Refrigeration and Air Conditioning

Nusselt number (NN) is given by

A. $${{\text{N}}_{\text{N}}} = \frac{{{\text{h}}l}}{{\text{k}}}$$

B. $${{\text{N}}_{\text{N}}} = \frac{{\mu {{\text{c}}_{\text{p}}}}}{{\text{k}}}$$

C. $${{\text{N}}_{\text{N}}} = \frac{{\rho {\text{V}}l}}{\mu }$$

D. $${{\text{N}}_{\text{N}}} = \frac{{{{\text{V}}^2}}}{{{\text{t}}{{\text{c}}_{\text{p}}}}}$$

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