The number 334 × 545 × 7p is divisible by 3340 then what is the minimum value of P?
A. 2
B. 4
C. 3
D. 1
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & \frac{{334 \times 545 \times 7p}}{{3340}} \cr & \Rightarrow \frac{{334 \times 545 \times 7p}}{{334 \times 10}} \cr & \Rightarrow \frac{{109 \times 7p}}{2} \cr & {\text{Go through by options take 2}} \cr & \Rightarrow \frac{{109 \times 72}}{2} \cr & {\text{So, answer is 2}} \cr} $$Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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