The number of candidates passing the examination from City F is what per cent of the total number of candidates appearing from all the cities together? ( rounded off to two digits after the decimal)

Total number of candidates from al the 5 cities
= {(1.25 + 3.14 + 1.08 + 2.27 + 1.85 + 2.73) × 100000}
= 12.32 × 100000
= 1232000
Number of candidates passing the exam from city F
$$\eqalign{ & = \frac{7}{12}\times2.73\times100000 \cr & = \frac{7\times273\times1000}{12} \cr & = 7\times91\times250 \cr & = 159250 \cr & \therefore \text{Required percentage} \cr & = \left(\frac{159250}{1232000}\times100\right)\% \cr & = \frac{15925}{1232}\% \cr & = 12.926\% \cr & \approx 12.93\% \cr} $$