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The number of female athletes who participated from Country E in the year 2009 was approximately what percentage of the total number of athletes who participated from Country B in the year 2008?
Answer & Solution
Correct Answer:
Option
B
Number of female athletes from E in 2009
= 9.2 × 100
= 920
Total number of athletes from B in 2008
= (11.4 + 8.4) × 100
= 19.8 × 100
= 1980
Let 920 = x% of 1980
Then,
$$\eqalign{ & \Rightarrow \frac{x}{100}\times1980 = 920 \cr & \Rightarrow x = \frac{920 × 100}{1980} \cr & \,\,\,\,\,\,\,\,\, = \frac{4600}{99}\% \cr & \,\,\,\,\,\,\,\,\, = 46.46\% \cr & \,\,\,\,\,\,\,\,\, \approx 46\% \cr} $$
= 9.2 × 100
= 920
Total number of athletes from B in 2008
= (11.4 + 8.4) × 100
= 19.8 × 100
= 1980
Let 920 = x% of 1980
Then,
$$\eqalign{ & \Rightarrow \frac{x}{100}\times1980 = 920 \cr & \Rightarrow x = \frac{920 × 100}{1980} \cr & \,\,\,\,\,\,\,\,\, = \frac{4600}{99}\% \cr & \,\,\,\,\,\,\,\,\, = 46.46\% \cr & \,\,\,\,\,\,\,\,\, \approx 46\% \cr} $$
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