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The number of oranges in three basket are in the ratio 3 : 4 : 5. In which ratio the no. of oranges in first two basket must be increased so that the new ratio becomes 5 : 4 : 3 ?
Answer & Solution
Correct Answer:
Option
D
Let, B1 : B2 : B3 = 3x : 4x : 5x and
B1 : B2 : B3 = 5y : 4y : 3y
Number of oranges remain constant in third basket as increase in oranges takes place only in first two baskets.
Hence, 5x = 3y x = $$\frac{3y}{5}$$ and, ∴ 3x : 4x : 5x (putting the vale of x)
= $$\frac{{9{\text{y}}}}{5}:\frac{{{\text{12y}}}}{5}:\frac{{{\text{15y}}}}{5}$$
= 9y : 12y : 15y
And,
5y : 4y : 3y (multiple by 5) → 25y : 20y : 15y
∴Increment in first basket = 16 And, Increment in second basket = 8 Thus, Required ratio = $$\frac{{16}}{8}$$ = 2 : 1
B1 : B2 : B3 = 5y : 4y : 3y
Number of oranges remain constant in third basket as increase in oranges takes place only in first two baskets.
Hence, 5x = 3y x = $$\frac{3y}{5}$$ and, ∴ 3x : 4x : 5x (putting the vale of x)
= $$\frac{{9{\text{y}}}}{5}:\frac{{{\text{12y}}}}{5}:\frac{{{\text{15y}}}}{5}$$
= 9y : 12y : 15y
And,
5y : 4y : 3y (multiple by 5) → 25y : 20y : 15y
∴Increment in first basket = 16 And, Increment in second basket = 8 Thus, Required ratio = $$\frac{{16}}{8}$$ = 2 : 1
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LoginNow the new ratio is 5:4:3
to compare the ratios, try to make the third component of each equal. Thus,
9:12:15
25:20:15
now you can see the change.
16 and 8. SO the ratio of increment= 2:1
Revised ratio is 5:4:3
Make the third component equal in both ratios :
Original ratio = 9:12:15
Revised ratio = 25:20:15
=> increase in First basket = 25 - 9 = 16
increase in second basket = 20 - 12 = 8
Required ratio = 16:8 = 2:1
(5:4:3)*5=25:20:15
ratio=25-9:20-12=16:8=2:1