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The number of persons having either blood group ‘A’ or blood group ‘B’ is:
Answer & Solution
Correct Answer:
Option
A
Person having blood group A or B
$$\eqalign{ & = \frac{129.6° + 72°}{360}\times150 \cr & = 84 \cr} $$
$$\eqalign{ & = \frac{129.6° + 72°}{360}\times150 \cr & = 84 \cr} $$
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