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The number, whose square is equal to the difference of the squares of 75.15 and 60.12, is = ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {\text{Let the number be = }}x \cr
& {\text{According to question,}} \cr
& {x^2} = {\left( {75.15} \right)^2} - {\left( {60.12} \right)^2} \cr
& \Rightarrow {x^2} = {\left( {75.15 + 60.12} \right)}\,{\left( {75.15 - 60.12} \right)} \cr
& \Rightarrow {x^2} = 135.27 \times 15.03 \cr
& \Rightarrow {x^2} = 2033.1081 \cr
& \Rightarrow x = 45.09 \cr} $$
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