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This question belongs to Electronics And Communications Engineering Analog Electronics

Analog Electronics

?

The percentage regulation of Half-wave rectifier is

A) $$\frac{{{{\text{V}}_{{\text{no load}}}} - {{\text{V}}_{{\text{load}}}}}}{{{{\text{V}}_{{\text{no load}}}}}} \times 100\% $$ B) $$\frac{{{{\text{V}}_{{\text{load}}}} - {{\text{V}}_{{\text{no load}}}}}}{{{{\text{V}}_{{\text{load}}}}}} \times 100\% $$ C) $$\frac{{{{\text{V}}_{{\text{no load}}}} - {{\text{V}}_{{\text{load}}}}}}{{{{\text{V}}_{{\text{load}}}}}} \times 100\% $$ D) $$\frac{{{{\text{V}}_{{\text{load}}}} - {{\text{V}}_{{\text{no load}}}}}}{{{{\text{V}}_{{\text{no load}}}}}} \times 100\% $$

Answer & Solution

Correct Answer: Option C

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