The present ratio of ages of A and B is 4 : 5. 18 years ago, this ratio was 11 : 16. Find the sum total of their present ages.
A. 90 years
B. 105 years
C. 110 years
D. 80 years
E. 95 years
Answer: Option A
Solution (By Examveda Team)
Let present age of A and B be 4x and 5x18 years ago their ages
$$\frac{{4x - 18}}{{5x - 18}} = \frac{{11}}{{16}}$$
Or, 64x - 288 = 55x - 198
Or, 64x - 55x = -198 + 288
Or, 9x = 90
Or, x = $$\frac{{90}}{9}$$ = 10
Sum of the present ages = 40 + 50 = 90 years
This Question Belongs to Arithmetic Ability >> Ratio
11x+18/16x+18 =4/ 5 then I get sum 18 ...y it is wrong?