The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, = Angular speed of crank, r = Radius of crank, = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)

This question belongs to Mechanical Engineering Theory Of Machine

Theory of Machine

The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)

A) $${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$ B) $${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$ C) $${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$ D) $${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$

Answer & Solution

Correct Answer: Option B

Let's discuss the solution. Join the discussion

Question posted by Examveda

Community

Join the Discussion

Join the discussion

No comments yet Be the first to discuss this question.

Keep Learning

The primary unbalanced force due to inertia of reciprocating parts in...

Join the Discussion

Related Questions on Theory of Machine