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The ratio of donors blood group ‘A’ to the average of the donors group ‘O’, ‘B’ and ‘AB’ is:
Answer & Solution
Correct Answer:
Option
D
Average of O, B, AB blood group
$$\eqalign{ & = \frac{100.8° + 129.6° + 57.6°}{3} \cr & = \frac{288°}{3} \cr & = 96° \cr & \therefore \text{Required ratio} \cr & = 72° : 96° \cr & = 3 : 4 \cr} $$
$$\eqalign{ & = \frac{100.8° + 129.6° + 57.6°}{3} \cr & = \frac{288°}{3} \cr & = 96° \cr & \therefore \text{Required ratio} \cr & = 72° : 96° \cr & = 3 : 4 \cr} $$
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