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The smallest 6-digit number exactly divisible by 111 is :
Answer & Solution
Correct Answer:
Option
C
The smallest 6-digit number is 100000
On dividing 100000 by 111, we get 100 as remainder.
So, the number to be added = (111 - 100) = 11
Hence, the required number = 100011
On dividing 100000 by 111, we get 100 as remainder.
So, the number to be added = (111 - 100) = 11
Hence, the required number = 100011
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