The torque transmitted by a hollow shaft of outer diameter (d1) and inner diameter (d2) is (where, = Maximum allowable shear stress)

This question belongs to Mechanical Engineering Strength Of Materials In ME

Strength of Materials in ME

The torque transmitted by a hollow shaft of outer diameter (d₁) and inner diameter (d₂) is (where, $$\tau $$ = Maximum allowable shear stress)

A) $$\frac{\pi }{4} \times \tau \times \frac{{{\text{d}}_1^4 - {\text{d}}_2^4}}{{{{\text{d}}_1}}}$$ B) $$\frac{\pi }{{16}} \times \tau \times \frac{{{\text{d}}_1^4 - {\text{d}}_2^4}}{{{{\text{d}}_1}}}$$ C) $$\frac{\pi }{{32}} \times \tau \times \frac{{{\text{d}}_1^4 - {\text{d}}_2^4}}{{{{\text{d}}_1}}}$$ D) $$\frac{\pi }{{64}} \times \tau \times \frac{{{\text{d}}_1^4 - {\text{d}}_2^4}}{{{{\text{d}}_1}}}$$

Answer & Solution

Correct Answer: Option B

Let's discuss the solution. Join the discussion

Question posted by Examveda

Community

Join the Discussion

Join the discussion

No comments yet Be the first to discuss this question.

Keep Learning

The torque transmitted by a hollow shaft of outer diameter (d1)...

The torque transmitted by a hollow shaft of outer diameter (d1) and inner diameter (d2) is (where, $$\tau $$ = Maximum allowable shear stress)

Join the Discussion

Related Questions on Strength of Materials in ME

The torque transmitted by a hollow shaft of outer diameter (d₁) and inner diameter (d₂) is (where, $$\tau $$ = Maximum allowable shear stress)