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The value of $$\frac{{40 + \frac{3}{4}{\text{ of }}32}}{{37 + \frac{3}{4}{\text{ of }}\left( {34 - 6} \right)}}$$ is:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& \frac{{40 + \frac{3}{4}{\text{ of }}32}}{{37 + \frac{3}{4}{\text{ of }}\left( {34 - 6} \right)}} \cr
& = \frac{{40 + 24}}{{37 + 21}} \cr
& = \frac{{64}}{{58}} \cr
& = \frac{{32}}{{29}} \cr
& = 1\frac{3}{{29}} \cr} $$
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