The value of $$7\frac{1}{2} \times \left( {3\frac{1}{5} \div 4\frac{1}{2}{\text{ of }}5\frac{1}{3}} \right) + \left[ {11 - \left( {\frac{5}{8} + 3 - 1\frac{1}{4}} \right)} \right] \div 5\frac{3}{4} - 5 \div 5 \times 5\,{\text{of }}5 \div 25\,{\text{is:}}$$

A. $$\frac{1}{2}$$

B. $$\frac{1}{{10}}$$

C. $$\frac{3}{{10}}$$

D. $$1\frac{1}{2}$$

Answer: Option D

Solution(By Examveda Team)

$$\begin{array}{l}7\frac{1}{2}\times \left(3\frac{1}{5}÷4\frac{1}{2}\text{ of }5\frac{1}{3}\right)+\left[11-\left(\frac{5}{8}+3-1\frac{1}{4}\right)÷5\frac{3}{4}-5÷5\times 5\text{of }5÷25\right]\\ =\frac{15}{2}\left(\frac{16}{5}÷\frac{9}{2}\text{ of }\frac{16}{3}\right)+\left[11-\left(\frac{5}{8}+3-\frac{3}{4}\right)÷\frac{23}{4}-5÷5\times \underset{}{\underbracket{5\text{of }5}}÷25\right]\\ =\frac{15}{2}\left(\frac{16}{5}÷24\right)+\left[11-\left(\frac{5}{8}+\frac{24-10}{8}\right)\right]÷\frac{23}{4}-5÷5\\ =\frac{15}{2}\left(\frac{2}{15}\right)+\left[\frac{88-19}{8}\right]÷\frac{23}{4}-1\\ =1+\frac{69}{8}\times \frac{4}{23}-1\\ =\frac{3}{2}\\ =1\frac{1}{2}\end{array}$$