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The value of following is, cos24° + cos55° + cos125° + cos204° + cos300° ?
Answer & Solution
Correct Answer:
Option
B
The value of,
cos24° + cos55° + cos125° + cos204° + cos300°
We know that, cos(180° $$ \pm $$ θ) = -cosθ
⇒ cos24° + cos55° + cos (180° - 55°) + cos (180° + 24°) + cos (360° - 60°)
⇒ cos24° + cos55° - cos55° - cos24° + cos60°
⇒ cos60°
⇒ $$\frac{1}{2}$$
cos24° + cos55° + cos125° + cos204° + cos300°
We know that, cos(180° $$ \pm $$ θ) = -cosθ
⇒ cos24° + cos55° + cos (180° - 55°) + cos (180° + 24°) + cos (360° - 60°)
⇒ cos24° + cos55° - cos55° - cos24° + cos60°
⇒ cos60°
⇒ $$\frac{1}{2}$$
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