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Calculus
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The value of the integral \[\int\limits_0^2 {\frac{{{{\left( {{\text{x}} - 1} \right)}^2}\sin \left( {{\text{x}} - 1} \right)}}{{{{\left( {{\text{x}} - 1} \right)}^2} + \cos \left( {{\text{x}} - 1} \right)}}} {\text{dx}}\]      is

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Correct Answer: Option B
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