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  1. Vijay Kumar
    Vijay Kumar :
    3 years ago

    6t^2-6t=dv/dt: d^2/dt^2=12t-6;at T1 12(1)-6 =6

Related Questions on Applied Mechanics and Graphic Statics

The resultant of two forces P and Q acting at an angle $$\theta $$, is

A. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{P}}\sin \theta $$

B. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta $$

C. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\tan \theta $$

D. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta } $$

E. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\sin \theta } $$