Two horses started simultaneously towards each other and meet each other 3 hr 20 mins later. How much time will it take the slower horse to cover the whole distance if the first arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of the first?
A. 10 hours
B. 5 hours
C. 15 hours
D. 6 hours
E. None of these
Answer: Option A
Solution(By Examveda Team)
Since, the two horses meet after 200 minutes; they cover 0.5% of the distance per minute (combined) or 30% distance per hour. This condition is satisfied only if the slower rider takes 10 hours (thereby covering 10% per hour) and the faster rider takes 5 hours.Join The Discussion
Comments ( 3 )
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
Explain it plz
let d = total distance each horse covered
let t = travel time of the slower horse
then
(t-5) = travel time of faster horse
d/t = speed of the slower horse
and
d/t-5 = speed of the faster horse
2 horses started simultaneously towards each other and meet each other 3hr20min later.
Slow horse dist + fast horse distance = total distance,
d/t*10/3+d/(t-5)*10/3 = d
we get t=10
Plz explain it by different method... I m not getting it... Plz help...