Two numbers are in the ratio 17 : 45, One - third of the smaller is less than $$\frac{1}{5}$$ of the bigger by 15. The smaller number is = ?
A. $$25\frac{1}{2}$$
B. $$67\frac{1}{2}$$
C. $$76\frac{1}{2}$$
D. $$86\frac{1}{2}$$
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{A}}:{\text{B}} \cr & 17:45 \cr & 17x:45x \cr & {\text{Given}} \cr & \Rightarrow 17x \times \frac{1}{3} + 15 = 45x \times \frac{1}{5} \cr & \Rightarrow \frac{{17x + 45}}{3} = 9x \cr & \Rightarrow 17x + 45 = 27x \cr & \Rightarrow 10x = 45 \cr & \Rightarrow x = \frac{{45}}{{10}} \cr & \therefore {\text{Smaller number is }} \cr & = \frac{{45}}{{10}} \times 17 \cr & = \frac{{765}}{{10}} \cr & = 76\frac{1}{2} \cr} $$Join The Discussion
Comments ( 1 )
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
45/10*17 not 14 please correct this option