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What is the average of first 93 natural numbers?
Answer & Solution
Correct Answer:
Option
C
Average of first 'n' natural number
$$\eqalign{ & = \frac{{\left( {n + 1} \right)}}{2} \cr & = \frac{{93 + 1}}{2} \cr & = 47 \cr} $$
$$\eqalign{ & = \frac{{\left( {n + 1} \right)}}{2} \cr & = \frac{{93 + 1}}{2} \cr & = 47 \cr} $$
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