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What was the average number of candidates appeared from zone T over all the years together?
Answer & Solution
Correct Answer:
Option
D
Average number of candidates appeared from T all over the years
$$\eqalign{ & = \frac{\left(6.2+6.2+6.4+7.8+9.9+11.8\right)\times100}{6} \cr & = \frac{48.3\times100}{6} \cr & = \frac{4830}{6} \cr & = 805 \cr} $$
$$\eqalign{ & = \frac{\left(6.2+6.2+6.4+7.8+9.9+11.8\right)\times100}{6} \cr & = \frac{48.3\times100}{6} \cr & = \frac{4830}{6} \cr & = 805 \cr} $$
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