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What was the ratio of the number of candidates appeared from zone P in the year 2005 to the number to the number of candidates qualified from zone S in the year 2007 ?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \text{Required ratio} \cr
& = \frac{3.2}{5.6} \cr
& = \frac{32}{56} \cr
& = \frac{4}{7} \cr
& = 4:7 \cr} $$
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