What will be the output given program?
#include<stdio.h>
void main()
{
int i = -10;
for(;i;printf("%d ", i++));
}
#include<stdio.h>
void main()
{
int i = -10;
for(;i;printf("%d ", i++));
}A. -10 to -1
B. -10 to infinite
C. -10 to 0
D. Complier error
Answer: Option A
Solution (By Examveda Team)
for loop can be initialized outside of the loop. Since until -1 value of i remain a non-zero value and hence the condition is true up to -1. But when i is further increases its value becomes 0 and condition becomes false and loop stops there.
Note:In C any non-zero value(positive or negative) evaluates to true and only zero value is evaluates to false.
This Question Belongs to C Program >> Control Structures
Miss. Anjali Saroha you are wrong because it will execute and gives output
-10-9-8-7-6-5-4-3-2-1
but in this the for loop have ; at the closing
it will create compiler error