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What will be the output of the following C code?
What will be the output of the following C code?
#include <stdio.h>
void main()
{
int i = 0;
if (i == 0)
{
printf("Hello");
break;
}
}
#include <stdio.h>
void main()
{
int i = 0;
if (i == 0)
{
printf("Hello");
break;
}
}
Answer & Solution
Correct Answer:
Option
D
The correct answer is D: Compile time error
Here's why:
In C, the `break` statement is used to exit loops (like `for`, `while`, or `do-while`) or `switch` statements.
It's designed to jump out of these control structures.
In this code, `break` is placed directly inside an `if` block, but not within any loop or `switch`.
The C compiler will detect that `break` is used in an invalid context.
Therefore, the program will result in a compile-time error, indicating that the `break` statement is misplaced. The program won't even run.
In summary: The `break` statement is only valid inside loops or `switch` statements.
Here's why:
In C, the `break` statement is used to exit loops (like `for`, `while`, or `do-while`) or `switch` statements.
It's designed to jump out of these control structures.
In this code, `break` is placed directly inside an `if` block, but not within any loop or `switch`.
The C compiler will detect that `break` is used in an invalid context.
Therefore, the program will result in a compile-time error, indicating that the `break` statement is misplaced. The program won't even run.
In summary: The `break` statement is only valid inside loops or `switch` statements.
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LoginIn this code, break; is used inside an if block, but not within any loop or switch, so the compiler will throw an error.