What will be the value of i and j after execution of following program?
#include<stdio.h>
void main()
{
int i, j;
for(i=0,j=0;i<10,j<20;i++,j++){
printf("i=%d %t j=%d", i, j);
}
}
#include<stdio.h>
void main()
{
int i, j;
for(i=0,j=0;i<10,j<20;i++,j++){
printf("i=%d %t j=%d", i, j);
}
}A. 10 10
B. 10 20
C. 20 20
D. Run time error
Answer: Option C
Solution (By Examveda Team)
comma operator is executed from left to right so until j<20 for loop statement is true, so both i and j are incremented.
So, i = 20 and j = 20.
This Question Belongs to C Program >> Control Structures
i=19 j=19
When we use The Comma Operator compiler will choose the right most value....(Associativity is Left to Right)....So though when i=10 the condition in the for loop i
when i=20 and j=20 the condition becomes file... when i run this snippet in my editor , it gave me i=19 and j=19 ...So the answer D is incorrect in my opinion.
What would be value of j after the following is executed? k=17; j=6; if (k < 10) j=8; j=j+1; j=j+2;
Please Explain comma operator concept
Comma operator executed left to right is correct.
comma operator is executed from left to right so until j