When a cylindrical vessel of radius (r) containing liquid is revolved about its vertical axis $$\omega $$ rad/s, then depth of parabola which the liquid assumes is
A. $$\frac{{\omega {\text{r}}}}{{2{\text{g}}}}$$
B. $$\frac{{{\omega ^2}{{\text{r}}^2}}}{{2{\text{g}}}}$$
C. $$\frac{{\omega {\text{r}}}}{{4{\text{g}}}}$$
D. $$\frac{{{\omega ^2}{{\text{r}}^2}}}{{4{\text{g}}}}$$
Answer: Option B

Please explain how it is