Which one of the following is true for 0° < θ < 90° ?
A. cosθ ≤ cos2θ
B. cosθ < cos2θ
C. cosθ > cos2θ
D. cosθ ≥ cos2θ
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{Put, }}\theta = {60^ \circ } \cr & \Rightarrow \cos \theta > {\cos ^2}\theta \cr & \Rightarrow \cos {60^ \circ } > {\cos ^2}{60^ \circ } \cr & \Rightarrow \frac{1}{2} > \frac{1}{4} \cr & \cos \theta > {\cos ^2}\theta \cr} $$Join The Discussion
Comments ( 3 )
Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
I also think correct answer would be D
At 60° option will be 'B'
Shouldn't the answer be D, for cos0 and cos 90