Which operator is used to return value from JSON columns after evaluating the path and unquoting the result?

Solution (By Examveda Team)

This question is about working with JSON data within MySQL. JSON (JavaScript Object Notation) is a popular format for storing data in a structured way.
MySQL provides operators to extract data from JSON columns.
The answer:
The correct operator is Option B: ->>.
Here's why:
* ->> This operator is specifically designed to extract data from a JSON column by following a path and then unquoting the result. This means it takes the JSON data, finds the specific value you're looking for based on the path you provide, and then removes any quotes around the extracted value.
Let's break it down:
* Path: Think of the path as a series of keys or indices that guide you to the desired value within the JSON structure. * Unquoting: JSON values are often enclosed in quotes. The ->> operator removes these quotes to give you the raw value.
Example:
Imagine you have a JSON column named "details" with the following data:
```json {"name": "Alice", "age": 30, "city": "New York"} ``` To get the value of the "name" key, you would use:
```sql SELECT details->>'name' FROM your_table; ``` This would return "Alice" (without the quotes).
Why the other options are incorrect:
* Option A: -> This operator is similar to ->>, but it does not unquote the result. It returns the value with the quotes still intact. * Option C: << and Option D: >> These operators are not used for accessing JSON data in MySQL.