?
2x - ky + 7 = 0 and 6x - 12y + 15 = 0 has no solution for;
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {\text{For no - solution,}} \cr
& \frac{{{a_1}}}{{{a_2}}} = \frac{{{b_1}}}{{{b_2}}} \ne \frac{{{c_1}}}{{{c_2}}} \cr
& 2x - ky + 7 = 0{\text{ and }}6x - 12y + 15 = 0 \cr
& \therefore \frac{2}{6} = \frac{{ - k}}{{12}} \cr
& k = 4 \cr} $$
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