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A container has 20% milk and 80% water in it. It is mixed with another sample (inequal quantity) having 80% milk and 20% water. What would be the milk content in the final mixture?
Answer & Solution
Correct Answer:
Option
C
\[\begin{array}{*{20}{c}}
{}&{{\text{Milk}}}&{{\text{Water}}}&{} \\
{}&{20}&{80}&{ = 100} \\
{{\text{New, mixture}}}&{\frac{{80}}{{100}}}&{\frac{{20}}{{100}}}&{ = 100} \\
{}&{50}&{50}&{ = 100}
\end{array}\]
$${\text{Milk}} = 50\% {\text{ Answer}}$$
$${\text{Milk}} = 50\% {\text{ Answer}}$$
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