A man covered a distance of 180 km in 4 hours on a bike. How much distance will be cover on a bicycle in 8 hours if he rides the bicycle at one-sixth the speed of the bike ?

Solution (By Examveda Team)

Speed of the bike :
$$\eqalign{ & = \left( {\frac{{180}}{4}} \right){\text{km/hr}} \cr & = {\text{45 km/hr}} \cr} $$
Speed of the bicycle :
$$\eqalign{ & = \left( {\frac{1}{6} \times 45} \right){\text{km/hr}} \cr & = 7.{\text{5 km/hr}} \cr} $$
∴ Required distance :
= (7.5 × 8) km
= 60 km