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A man reduces his speed from 20 kmph to 18 kmph. So, he takes 10 minutes more than the normal time. what is the distance traveled by him.
Answer & Solution
Correct Answer:
Option
A
Usual time = 9 × 10 = 90 min = $$\frac{3}{2}$$ h
Thus,
Distance traveled = Speed × time = $$20 \times \frac{3}{2}$$ = 30 km.
Alternatively,
As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.
10% = 10 min
100% = 100 min.
Now,
Distance traveled by him,= $$\frac{{100}}{{60}} \times 18$$
= 30 km.
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LoginTIME=18:20=9:10[GAP 1]
BUT WE NEED GAAP 10
SO TIME=90:100
DISTANCE=20*90/60=30 KM/HR...(ANS)