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A metallic solid spherical ball of radius 3 cm is melted...

This question belongs to Arithmetic Ability Mensuration 3D
Mensuration 3D
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A metallic solid spherical ball of radius 3 cm is melted recast into three spherical balls. The radii of two of these balls are 2 cm and 1.5 cm. What is the surface area (in cm2) of the third ball?

Answer & Solution
Correct Answer: Option C
$$\frac{4}{3}$$π × 3 × 3 × 3 = $$\frac{4}{3}$$π × 23 + $$\frac{4}{3}$$π × (1.5)3 + $$\frac{4}{3}$$π × r3
27 = 8 + 3.375 + r3
15.625 = r3
r = 2.5 cm
∴ The surface area of the third ball = 4π × 2.5 × 2.5 = 25π cm2
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