A monkey climbs a 60 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top?

Solution (By Examveda Team)

Monkey climbs 6 m in 1^st minute and slips down 3 m in next minute
i.e. Monkey climbs 3 meter in 2 minute then he climbs in one minute,
= $$\frac{3}{2}$$ m.
But in the last minute he climbs 6 m as he gets on the top so there is no slip.
Time required = $$2 \times \frac{{54}}{3} + \frac{6}{6}$$   = 37 minutes.