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A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer & Solution
Correct Answer:
Option
B
Area of the park = (60 x 40) m2 = 2400 m2
Area of the lawn = 2109 m2
∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
⇒ x2 - 100x + 291 = 0
⇒ (x - 97)(x - 3) = 0
⇒ x = 3 m
Area of the lawn = 2109 m2
∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
⇒ x2 - 100x + 291 = 0
⇒ (x - 97)(x - 3) = 0
⇒ x = 3 m
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