# A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A. 2.91 m

B. 3 m

C. 5.82 m

D. None of these

**Answer: Option B **

__Solution(By Examveda Team)__

Area of the park = (60 x 40) m^{2}= 2400 m

^{2}

Area of the lawn = 2109 m

^{2}

∴ Area of the crossroads = (2400 - 2109) m

^{2}= 291 m

^{2}

Let the width of the road be

*x*metres. Then,

60

*x*+ 40

*x*-

*x*

^{2}= 291

⇒

*x*

^{2}- 100

*x*+ 291 = 0

⇒ (

*x*- 97)(

*x*- 3) = 0

⇒

*x*= 3 m

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## Comments ( 1 )

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The correct answer is 2.91 option A