A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m, then the altitude of the triangle is :
A. 10$$\sqrt 2 $$ m
B. 100 m
C. 100$$\sqrt 2 $$ m
D. 200 m
Answer: Option D
Solution (By Examveda Team)
Let the altitude of the triangle be h1 and base of each be b.Then,
$$\frac{1}{2}$$ × b1 × h1 = b × h2, where h2 = 100 m
⇔ h1 = 2 h2
⇔ h1 = (2 × 100) m
⇔ h1 = 200 m
This Question Belongs to Arithmetic Ability >> Area
Join The Discussion