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A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m, then the altitude of the triangle is :
Answer & Solution
Correct Answer:
Option
D
Let the altitude of the triangle be h1 and base of each be b.
Then,
$$\frac{1}{2}$$ × b1 × h1 = b × h2, where h2 = 100 m
⇔ h1 = 2 h2
⇔ h1 = (2 × 100) m
⇔ h1 = 200 m
Then,
$$\frac{1}{2}$$ × b1 × h1 = b × h2, where h2 = 100 m
⇔ h1 = 2 h2
⇔ h1 = (2 × 100) m
⇔ h1 = 200 m
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